number game in python

This is not done,  But it is working.... Unless you give it bad input.
I don't have a lot of those errors worked out yet. 
I want a way to compare the answers given to ones already given, but It mucks up the code when I include it. 

Really thought translating the one I did in JAVA to python would be easier.... It's not.
Have to move on,  come back to this later.

import random

def guess_my_number():

start = print("Guess my number! range = 0-100. ")

print(('.')*15)

cpu_number = random.randint(0,100)

print(f" computers number = {cpu_number}.")

guesses = []

count = 1

if check_for_yes("play?"):

first_guess = int(input("First guess....:"))

if first_guess != cpu_number:

guesses.append(first_guess)

count += 1

stopper = True

elif first_guess == cpu_number:

print("Holy crap. Are you psychic?")

stopper = False

else: stopper = False

your_guess = int(input("Next guess....:"))

while stopper:

#if look_for_equals(guesses, your_guess):

#print(count)

#print(f"you already guessed the number: {your_guess}")

#your_guess = int(input("try again ..."))

if count == 10:

print(f"Sorry, my number was {cpu_number}")

stopper = False

elif your_guess == cpu_number:

print(f"You win! You got the answer in {count} trys!")

stopper = False

elif your_guess > cpu_number: #and your_guess != cpu_number:

your_guess = int(input("Your guess is too high. Try again."))

guesses.append(your_guess)

count += 1

elif your_guess < cpu_number: #and your_guess != cpu_number:

your_guess = int(input("Your number is too low. Try again."))

count +=1

guesses.append(your_guess)

else:

print("Error.")

def check_for_yes(playing):

playing = input("Do you want to play? yes, no, quit.")

if playing.lower() in ['yes', 'y']:

return True

elif playing.lower() in ['quit', 'q', 'no', 'n']:

print("Bored already? Later!.")

return False

else:

print("Else is executing")

exit()

def look_for_equals(somelist, arg):

if arg in somelist:

return True

else:

return False

guess_my_number()